Welcome back Mathletes! It's finally starting to feel like spring is in full swing here in the Midwest, so that means its time for gardens to start being planted. This week we have some fun math problems all about gardening!
Lower Elementary:
Question: William has 3 fruit trees in his garden. He picks 8 apples from the apple tree, 6 pears from the pear tree, and 7 limes from the lime tree. How many pieces of fruit did William pick?
Upper Elementary:
Question: Harrison has a full 3–gallon watering can. He uses 5/8 of the water on the gardenias in his garden. How much water did the gardenias get?
Middle School:
Question: Lily is making labels for the plants in her garden. Each label is made of a white 3″ × 5″ laminated against a colorful 5″ × 8″ card. What is the area of the front of each label that isn’t covered by the white card?
Algebra and Up:
Question: Cameron is selling flowers from his garden. By selling large bouquets for $21 and small bouquets for $15, he makes $540. If he sells a total of 30 bouquets, how many large bouquets did Cameron sell?
When you are ready for the answers check below!!
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Lower Elementary:
Answer: 21 pieces of fruit
Solution: To find the total, add the apples and the pears, and then add the limes: 8 + 6 = 14. Then, 14 + 7 = 21.
Upper Elementary:
Answer: 15 pints
Solution: First we converted the amount of water from gallons into pints because a pint is 1/8 of a gallon. Harrison had 24 pints of water. Then we found 5/8 of 24 and determined Harrison used 15 pints of water.
Middle School:
Answer: 25 square inches
Solution: First, we need to find the area of the larger card. That’s 5 × 8 = 40 square inches. Next, we subtract the part that’s covered by the white card, which is 3 × 5 = 15 square inches. Then we subtract the area of the small card from the larger card, which gives us 40 – 15 = 25 square inches.
Algebra and Up:
Answer: 15 large bouquets
Solution: We can use the equations 21L + 15S = 540 and L + S = 30 to solve for both variables. First, we solve for S in the second equation. That gives us that S = 30 – L. We can plug that value of S into the original equation, so 21L + 15(30 – L) = 540. If we solve for L, we get 15.
Thanks for hanging out with us this week Mathletes!
If you would like more information about Mathnasium of Ankeny and what we do, feel free to call us at (515) 478-3552 or click one of the buttons below!
